0=24x^2+168x+288

Solution for 0=24x^2+168x+288 equation:

0=24x^2+168x+288

We move all terms to the left:

0-(24x^2+168x+288)=0

We add all the numbers together, and all the variables

-(24x^2+168x+288)=0

We get rid of parentheses

-24x^2-168x-288=0

a = -24; b = -168; c = -288;
Δ = b2-4ac
Δ = -1682-4·(-24)·(-288)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-24}{2*-24}=\frac{144}{-48}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+24}{2*-24}=\frac{192}{-48}
=-4
$